For this roulette winning strategy to work, you need to make larger bets or win in order to recoup losses, and if you can’t do either then you want to walk away. The Reverse Martingale Roulette Strategy As might be expected given the name, this method of roulette gameplay is the opposite of the Martingale Strategy.

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Honestly, it’s not that different. Winning at electronic roulette is as likely to happen as at the land-based one. So, what’s the deal? Electronic roulette, unlike the live casino one, is powered by RNG software. So the only way to win in roulette–and this is completely random, never guaranteed–is to bet on less than all the numbers on the wheel. You also want to play bets that pay better than even money. You can place a variety of bets, but most of them aren’t worthwhile. Betting on single numbers is a bad idea.

It’s often described as a game of luck, but a scientist has revealed that there may be ways to increase your chance of beating the house at roulette. During a Q&A on Quora, Professor Richard. How to win when playing roulette: The strategy presented here on this video offer some good ways to win easily on roulette, and is a 'low risk strategy', it.

Why can you not win in online roulette? In this article, we present a mathematical proof of the negative mathematical expectation on the course when you play in roulette. We shall also explore the Mathematical evidence of ineffectiveness while using the winning strategies. So, why is it impossible to win at roulette? The basic line is that there are 37 numbers on the field (0-36) and payments are paid 36 to 1. So, every time you bet in, statistically, you are losing 2,7% from the betting amount (even if you have won in the current spin). If you want to check our mathematical explanations, read further.

Why cannot you succeed in roulette via using strategies?

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Let's consider all possible common bets in roulette as the mathematical proof of the impossibility to win in roulette and determine their ME (Mathematical expectation) result.

In the general case, I of any bet in roulette can be calculated using the classical formula (1):

, (1)

• Where is xi– event I,
• Pi– The probability of the event I,
• К – The total number of events forming a complete group.

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The mathematical expectation of the European version:

The formula (1) for ME of any bets on 'European roulette' can be converted taking into the full probability, not collaborative events, that is Pwin.+ Ploss.=1, to the view with the game for N sectors (rooms), is equal to:
... (2)

Since the probability of winning Pwin in 'European roulette', while you are playing for N sectors (rooms), is equal to:

, that finally, we obtain the expression for ME for ANY bet in 'European roulette', when you are playing for N sectors (rooms), is equal to:... (3)
Let's calculate ME for each 'simple' (basic) bet in 'European roulette' (a wheel with one zero). The result of ME calculation for average basic bets is presented in table 1.

The mathematical expectation for the bets:

Table 1. Calculation of ME for 'simple' bets.

№	«Simple» bet	Winning		Loss	Calculation МО, у.е.
		Payout	Probability	Probability
1.	Straight-Up	35:1	1/37	36/37	=35×1/37-36/37= -1/37
2.	Split	17:1	2/37	35/37	=17×2/37-35/37= -1/37
3.	Street	11:1	3/37	34/37	=11×3/37-34/37= -1/37
4.	Corner	8:1	4/37	33/37	=8×4/37-33/37= -1/37
5.	Six Line	5:1	6/37	31/37	=5×6/37-31/37= -1/37
6.	Column & Dozens	2:1	12/37	25/37	=2×12/37-25/37= -1/37
7.	Even Chance	1:1	18/37	19/37	=1×18/37-19/37= -1/37

As can we see from the table – ME is exactly equal to the value obtained by the formula (3). Let's sum up the results.

The player always loses even when he wins

If the gambler is playing at 'European roulette', (no matter where and how much he puts), he ALWAYS loses 1/37 part of the bet (bets). At the same ME of the game, it is not dependent on the outcome of the spin; that is, the player loses even when he wins. Or in other words, the player ALWAYS loses when he makes a bet at 'European Roulette' regardless of the outcome of the current spin.

Using the strategies of the bets:

For the mathematical proof of the winning's impossibility at 'European roulette' or 'American Roulette,' it is enough to expand any betting strategy on the 'basic' bet. As ME result of all bets is negative and equals -1/37 the size of the stake, then the total expectation of the game result will be negative and equal -1/37. The sum of all bets made by the player or -1/37 from the value of the average stake multiplied by the number of spins played by a gambler.

Assessing the ME of any strategy is enough to determine the value of the average bet while you are playing according to this strategy and taking into consideration all the rules of the transition from bet to bet, and multiplying the result by -1/37. The value of the average bet and sum of all of the bets are positive values; therefore ME is always less than zero, that is ME£0 and less than ME£-1/37 if used the progression because the average rate is bigger than 1.

Dispersion

Let's calculate the variance for any bet in 'European roulette', depending on how many sectors N (rooms) puts the gambler. Use the variance to determine the optimal Bank Kelly criterion for playing 'European roulette'.

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Bank on Kelly's criterion shows what should be the gambler's bank to the total balance of all games aspired to infinity.

In the general case, the variance of the player who is playing at the 'European roulette' in N sectors (rooms) can be calculated by the expression:

. (4)

The formula (4) for the variance D of any bets on the 'European roulette' can be converted taking into the full probability, not joint events, that is Pwin.+ Ploss.=1, to the mind:

. (5)

Since the probability of winning Pwin in the 'European Roulette' while you are playing for N sectors (rooms) is equal to:

, finally, we get the expression for the dispersion D of any bet at the 'European roulette' when you are playing for N sectors (rooms), is:. (6)

The magnitude of dispersion D has a positive value throughout the range of games in N sectors. That is an important detail.

Where it is possible to calculate the required bank for the game at 'European roulette' using Kelly's criterion:

. (7)

Using the expressions (3) and (6), we finally obtain the expression:

(8).

The formula (8) shows that the optimal amount of the bank, according to Kelly's criterion for playing at 'European Roulette' is a negative value.

Conclusion:

If the optimal value of the gambler's bank following Kelly's criterion is negative, then playing at 'European roulette' is generally not necessary, since the overall result of the balance of all players` games approach to zero, or the player has to lose all his money during the long game.

To assess the 'attractiveness' of the gambling, you can use generalised criteria, which is obtained as the ratio of required the gambler's bank following Kelly's criterion to the mathematical expectation of the game result that is:

(9).

This expression (9) can be understood that the smaller size of the gambler's bank at the mathematical expectation, the 'better' will be a game for the player. This optimal criterion can be interpreted as the criteria of minimal specific player's bank per unit of profit from the game.

The optimal criteria of the Кoptima game can only be used for evaluation of games with a positive expectation! If the game has a negative MT, it will not attract the attention of the gamblers. For 'European roulette' MT -1/37, that is less than zero, so 'European roulette' as the game is not 'attractive' for gamblers. That is why it is impossible to win in roulette, regardless of which betting strategies and tactics selection of items you use.

Note: the formula (3), (5) and (8) can be obtained for 'American roulette' with two sectors of zero: 0 and 00.

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